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5t^2+7t-60=0
a = 5; b = 7; c = -60;
Δ = b2-4ac
Δ = 72-4·5·(-60)
Δ = 1249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1249}}{2*5}=\frac{-7-\sqrt{1249}}{10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1249}}{2*5}=\frac{-7+\sqrt{1249}}{10} $
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